MathematicsHard57×since 2003Q3969For some θ∈(0,π2)\theta \in \left( {0,{\pi \over 2}} \right)θ∈(0,2π), if the eccentricity of the hyperbola, x²–y²sec²θ\thetaθ = 10 is 5\sqrt 55 times the eccentricity of the ellipse, x²sec²θ\thetaθ + y² = 5, then the length of the latus rectum of the ellipse, is :A30\sqrt {30}30B262\sqrt 626C453{{4\sqrt 5 } \over 3}345D253{{2\sqrt 5 } \over 3}325Check answerSkip