MathematicsMedium178×since 2002Q5187For 0<c<b<a0 < c < b < a0<c<b<a, let (a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0(a+b-2 c) x^2+(b+c-2 a) x+(c+a-2 b)=0(a+b−2c)x2+(b+c−2a)x+(c+a−2b)=0 and α≠1\alpha \neq 1α=1 be one of its root. Then, among the two statements (I) If α∈(−1,0)\alpha \in(-1,0)α∈(−1,0), then bbb cannot be the geometric mean of aaa and ccc (II) If α∈(0,1)\alpha \in(0,1)α∈(0,1), then bbb may be the geometric mean of aaa and cccAonly (II) is trueBBoth (I) and (II) are trueConly (I) is trueDNeither (I) nor (II) is trueCheck answerSkip