PhysicsEasy66×since 2002Q6907For a transistor α\alphaα and β\betaβ are given as α=ICIE\alpha = {{{I_C}} \over {{I_E}}}α=IEIC and β=ICIB\beta = {{{I_C}} \over {{I_B}}}β=IBIC. Then the correct relation between α\alphaα and β\betaβ will be :Aα=1−ββ\alpha = {{1 - \beta } \over \beta }α=β1−βBβ=α1−α\beta = {\alpha \over {1 - \alpha }}β=1−ααCαβ=1\alpha \beta = 1αβ=1Dα=β1−β\alpha = {\beta \over {1 - \beta }}α=1−ββCheck answerSkip