PhysicsEasy66×since 2002Q6892For a transistor amplifier in common emitter configuration for load impedance of 1k Ω1k\,\Omega1kΩ (hfe=50\left( {{h_{fe}} = 50} \right.(hfe=50 and hoe=25)\left. {{h_{oe}} = 25} \right)hoe=25) the current gain isA−24.8-24.8−24.8B−15.7-15.7−15.7C−5.2-5.2−5.2D−48.78-48.78−48.78Check answerSkip