ChemistryMedium49×since 2002Q420For a reaction at equilibrium A(g) ⇌\rightleftharpoons⇌ B(g) + 12{1 \over 2}21 C(g) the relation between dissociation constant (K), degree of dissociation (α\alphaα) and equilibrium pressure (p) is given by :AK=α12p32(1+32α)12(1−α)K = {{{\alpha ^{{1 \over 2}}}{p^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(1+23α)21(1−α)α21p23BK=α32p12(2+α)12(1−α)K = {{{\alpha ^{{3 \over 2}}}{p^{{1 \over 2}}}} \over {{{\left( {2 + \alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(2+α)21(1−α)α23p21CK=(α p)32(1+32α)12(1−α)K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + {3 \over 2}\alpha } \right)}^{{1 \over 2}}}(1 - \alpha )}}K=(1+23α)21(1−α)(αp)23DK=(α p)32(1+α)(1−α)12K = {{{{(\alpha \,p)}^{{3 \over 2}}}} \over {{{\left( {1 + \alpha } \right)}}{{(1 - \alpha )}^{{1 \over 2}}}}}K=(1+α)(1−α)21(αp)23Check answerSkip