PhysicsMedium42×since 2002Q6276For a particle in uniform circular motion, the acceleration a→\overrightarrow aa at any point P(R, θ\thetaθ) on the circular path of radius R is (when θ\thetaθ is measured from the positive x-axis and v is uniform speed) :A−v2Rsinθi^+v2Rcosθj^- {{{v^2}} \over R}\sin \theta \widehat i + {{{v^2}} \over R}\cos \theta \widehat j−Rv2sinθi+Rv2cosθjB−v2Rcosθi^+v2Rsinθj^- {{{v^2}} \over R}\cos \theta \widehat i + {{{v^2}} \over R}\sin \theta \widehat j−Rv2cosθi+Rv2sinθjC−v2Rcosθi^−v2Rsinθj^- {{{v^2}} \over R}\cos \theta \widehat i - {{{v^2}} \over R}\sin \theta \widehat j−Rv2cosθi−Rv2sinθjD−v2Ri^+v2Rj^- {{{v^2}} \over R}\widehat i + {{{v^2}} \over R}\widehat j−Rv2i+Rv2jCheck answerSkip