ChemistryMedium49×since 2002Q422For a concentrated solution of a weak electrolyte (Keq =\mathrm{K}_{\text {eq }}=Keq = equilibrium constant) A2B3\mathrm{A}_{2} \mathrm{B}_{3}A2B3 of concentration 'ccc', the degree of dissociation 'α\alphaα' is :A(Keq25c2)15\left(\frac{K_{e q}}{25 c^{2}}\right)^{\frac{1}{5}}(25c2Keq)51B(Keq108c4)15\left(\frac{K_{e q}}{108 c^{4}}\right)^{\frac{1}{5}}(108c4Keq)51C(Keq5c4)15\left(\frac{K_{e q}}{5 c^{4}}\right)^{\frac{1}{5}}(5c4Keq)51D(Keq6c5)15\left(\frac{K_{e q}}{6 c^{5}}\right)^{\frac{1}{5}}(6c5Keq)51Check answerSkip