MathematicsEasy74×since 2004Q3745Equation of the ellipse whose axes of coordinates and which passes through the point (−3,1)(-3,1)(−3,1) and has eccentricity 25\sqrt {{2 \over 5}}52 is :A5x2+3y2−48=05{x^2} + 3{y^2} - 48 = 05x2+3y2−48=0B3x2+5y2−15=03{x^2} + 5{y^2} - 15 = 03x2+5y2−15=0C5x2+3y2−32=05{x^2} + 3{y^2} - 32 = 05x2+3y2−32=0D3x2+5y2−32=03{x^2} + 5{y^2} - 32 = 03x2+5y2−32=0Check answerSkip