MathematicsMedium249×since 2002Q2436Equation of a plane at a distance 221\sqrt {{2 \over {21}}}212 from the origin, which contains the line of intersection of the planes x −-− y −-− z −-− 1 = 0 and 2x + y −-− 3z + 4 = 0, is :A3x−y−5z+2=03x - y - 5z + 2 = 03x−y−5z+2=0B3x−4z+3=03x - 4z + 3 = 03x−4z+3=0C−x+2y+2z−3=0- x + 2y + 2z - 3 = 0−x+2y+2z−3=0D4x−y−5z+2=04x - y - 5z + 2 = 04x−y−5z+2=0Check answerSkip