MathematicsHard66×since 2002Q4083cot−1(cosα)−tan−1(cosα)=x,{\cot ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) - {\tan ^{ - 1}}\left( {\sqrt {\cos \alpha } } \right) = x,cot−1(cosα)−tan−1(cosα)=x, then sin x is equal to :Atan2(α2){\tan ^2}\left( {{\alpha \over 2}} \right)tan2(2α)Bcot2(α2){\cot ^2}\left( {{\alpha \over 2}} \right)cot2(2α)Ctanα\tan \alphatanαDcot(α2)cot\left( {{\alpha \over 2}} \right)cot(2α)Check answerSkip