MathematicsEasy115×since 2008Q4353Consider the two statements : (S1) : (p →\to→ q) ∨\vee∨ (∼\sim∼ q →\to→ p) is a tautology . (S2) : (p ∧\wedge∧ ∼\sim∼ q) ∧\wedge∧ (∼\sim∼ p ∧\wedge∧ q) is a fallacy. Then :Aonly (S1) is true.Bboth (S1) and (S2) are false.Cboth (S1) and (S2) are true.Donly (S2) is true.Check answerSkip