MathematicsHard249×since 2002Q2532Consider the line L\mathrm{L}L passing through the points (1,2,3)(1,2,3)(1,2,3) and (2,3,5)(2,3,5)(2,3,5). The distance of the point (113,113,193)\left(\frac{11}{3}, \frac{11}{3}, \frac{19}{3}\right)(311,311,319) from the line L\mathrm{L}L along the line 3x−112=3y−111=3z−192\frac{3 x-11}{2}=\frac{3 y-11}{1}=\frac{3 z-19}{2}23x−11=13y−11=23z−19 is equal toA6B3C5D4Check answerSkip