PhysicsEasy105×since 2002Q7111Consider a light ray travelling in air is incident into a medium of refractive index 2n\sqrt{2n}2n. The incident angle is twice that of refracting angle. Then, the angle of incidence will be :Asin−1(n){\sin ^{ - 1}}\left( {\sqrt n } \right)sin−1(n)Bcos−1(n2){\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)cos−1(2n)Csin−1(2n){\sin ^{ - 1}}\left( {\sqrt {2n} } \right)sin−1(2n)D2cos−1(n2)2{\cos ^{ - 1}}\left( {\sqrt {{n \over 2}} } \right)2cos−1(2n)Check answerSkip