At any instant the velocity of a particle of mass … is …. If the force acting on the particle at … is …. Then the value of … will be:

Option D. Given the velocity vector of a particle …, the acceleration … is the derivative of the velocity vector with respect to time. So, we have:

Laws of Motion

JEE Main 2023 · 8 Apr, Morning shift · Q7598

PhysicsMedium68×since 2002Q7598

At any instant the velocity of a particle of mass

500 \mathrm{~g}

\left(2 t \hat{i}+3 t^{2} \hat{j}\right) \mathrm{ms}^{-1}

. If the force acting on the particle at

t=1 \mathrm{~s}

(\hat{i}+x \hat{j}) \mathrm{N}

. Then the value of

x

will be: