PhysicsMedium183×since 2002Q5956An α\alphaα-particle of energy 555 MeVMeVMeV is scattered through 180∘{180^ \circ }180∘ by a fixed uranium nucleus. The distance of closest approach is of the order ofA10−12 cm{10^{ - 12}}\,cm10−12cmB10−10 cm{10^{ - 10}}\,cm10−10cmC1A1A1AD10−15a cm{10^{ - 15a}}\,cm10−15acmCheck answerSkip