PhysicsEasy145×since 2002Q6582An α\alphaα-particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:Aλα>λp<λe{\lambda _\alpha } > {\lambda _p} < {\lambda _e}λα>λp<λeBλα>λp>λe{\lambda _\alpha } > {\lambda _p} > {\lambda _e}λα>λp>λeCλα=λp=λe{\lambda _\alpha } = {\lambda _p} = {\lambda _e}λα=λp=λeDλα<λp<λe{\lambda _\alpha } < {\lambda _p} < {\lambda _e}λα<λp<λeCheck answerSkip