PhysicsEasy148×since 2002Q7937An object of mass m is suspended at the end of a massless wire of length L and area of crosssection A. Young modulus of the material of the wire is Y. If the mass is pulled down slightly its frequency of oscillation along the vertical direction is :Af=12πYAmLf = {1 \over {2\pi }}\sqrt {{{YA} \over {mL}}}f=2π1mLYABf=12πmLYAf = {1 \over {2\pi }}\sqrt {{{mL} \over {YA}}}f=2π1YAmLCf=12πYLmAf = {1 \over {2\pi }}\sqrt {{{YL} \over {mA}}}f=2π1mAYLDf=12πmAYLf = {1 \over {2\pi }}\sqrt {{{mA} \over {YL}}}f=2π1YLmACheck answerSkip