PhysicsEasy55×since 2003Q6677An ideal coil of 10H10H10H is connected in series with a resistance of 5Ω5\Omega5Ω and a battery of 5V5V5V. 222 second after the connection is made, the current flowing in ampere in the circuit isA(1−e−1)\left( {1 - {e^{ - 1}}} \right)(1−e−1)B(1−e)\left( {1 - e} \right)(1−e)CeeeDe−1{{e^{ - 1}}}e−1Check answerSkip