PhysicsEasy145×since 2002Q6572An electron with speed v and a photon with speed c have the same de-Broglie wavelength. If the kinetic energy and momentum of electron are E_e and p_e and that of photon are E_ph and p_ph respectively. Which of the following is correct?AEeEph=2cv{{{E_e}} \over {{E_{ph}}}} = {{2c} \over v}EphEe=v2cBEeEph=v2c{{{E_e}} \over {{E_{ph}}}} = {v \over {2c}}EphEe=2cvCpepph=2cv{{{p_e}} \over {{p_{ph}}}} = {{2c} \over v}pphpe=v2cDpepph=v2c{{{p_e}} \over {{p_{ph}}}} = {v \over {2c}}pphpe=2cvCheck answerSkip