PhysicsEasy145×since 2002Q6552An electron (of mass m) and a photon have the same energy E in the range of a few eV. The ratio of the de-Broglie wavelength associated with the electron and the wavelength of the photon is (c = speed of light in vaccuum)A1c(2Em)12{1 \over c}{\left( {{{2E} \over m}} \right)^{{1 \over 2}}}c1(m2E)21B1c(E2m)12{1 \over c}{\left( {{E \over {2m}}} \right)^{{1 \over 2}}}c1(2mE)21C(E2m)12{\left( {{E \over {2m}}} \right)^{{1 \over 2}}}(2mE)21Dc(2mE)12c{\left( {2mE} \right)^{{1 \over 2}}}c(2mE)21Check answerSkip