PhysicsEasy145×since 2002Q6559An electron of mass m and a photon have same energy E. The ratio of wavelength of electron to that of photon is : (c being the velocity of light)A1c(2mE)1/2{1 \over c}{\left( {{{2m} \over E}} \right)^{1/2}}c1(E2m)1/2B1c(E2m)1/2{1 \over c}{\left( {{E \over {2m}}} \right)^{1/2}}c1(2mE)1/2C(E2m)1/2{\left( {{E \over {2m}}} \right)^{1/2}}(2mE)1/2Dc(2mE)1/2c{(2mE)^{1/2}}c(2mE)1/2Check answerSkip