PhysicsMedium145×since 2002Q6575An electron (mass m\mathrm{m}m) with an initial velocity v⃗=v0i^(v0>0)\vec{v}=v_{0} \hat{i}\left(v_{0}>0\right)v=v0i^(v0>0) is moving in an electric field E⃗=−E0i^(E0>0)\vec{E}=-E_{0} \hat{i}\left(E_{0}>0\right)E=−E0i^(E0>0) where E0E_{0}E0 is constant. If at t=0\mathrm{t}=0t=0 de Broglie wavelength is λ0=hmv0\lambda_{0}=\frac{h}{m v_{0}}λ0=mv0h, then its de Broglie wavelength after time t is given byAλ0\lambda_{0}λ0Bλ0(1+eE0tmv0)\lambda_{0}\left(1+\frac{e E_{0} t}{m v_{0}}\right)λ0(1+mv0eE0t)Cλ0t\lambda_{0} tλ0tDλ0(1+eE0tmv0)\frac{\lambda_{0}}{\left(1+\frac{e E_{0} t}{m v_{0}}\right)}(1+mv0eE0t)λ0Check answerSkip