PhysicsMedium145×since 2002Q6551An electron (mass m) with initial velocity v→=v0i^+v0j^\overrightarrow v = {v_0}\widehat i + {v_0}\widehat jv=v0i+v0j is in an electric field E→=−E0k^\overrightarrow E = - {E_0}\widehat kE=−E0k. If λ0\lambda _0λ0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :Aλ01+e2E2t2m2v02{{{\lambda _0} } \over {\sqrt {1 + {{{e^2}{E^2}{t^2}} \over {{m^2}v_0^2}}} }}1+m2v02e2E2t2λ0Bλ021+e2E2t2m2v02{{{\lambda _0}\sqrt 2 } \over {\sqrt {1 + {{{e^2}{E^2}{t^2}} \over {{m^2}v_0^2}}} }}1+m2v02e2E2t2λ02Cλ01+e2E2t22m2v02{{{\lambda _0} } \over {\sqrt {1 + {{{e^2}{E^2}{t^2}} \over {2{m^2}v_0^2}}} }}1+2m2v02e2E2t2λ0Dλ02+e2E2t2m2v02{{{\lambda _0}} \over {\sqrt {2 + {{{e^2}{E^2}{t^2}} \over {{m^2}v_0^2}}} }}2+m2v02e2E2t2λ0Check answerSkip