PhysicsEasy145×since 2002Q6547An electron, a doubly ionized helium ion (He⁺⁺) and a proton are having the same kinetic energy. The relation between their respective de-Broglie wavelengths λ\lambdaλ_e, λ\lambdaλHe⁺⁺ and λ\lambdaλ_p is :Aλ\lambdaλ_e > λ\lambdaλHe⁺⁺ > λ\lambdaλ_pBλ\lambdaλ_e < λ\lambdaλ_p < λ\lambdaλHe⁺⁺Cλ\lambdaλ_e > λ\lambdaλ_p > λ\lambdaλHe⁺⁺Dλ\lambdaλ_e < λ\lambdaλHe⁺⁺ = λ\lambdaλ_pCheck answerSkip