MathematicsHard202×since 2002Q5701An arc PQ of a circle subtends a right angle at its centre O. The mid point of the arc PQ is R. If OP→=u→,OR→=v→\overrightarrow {OP} = \overrightarrow u ,\overrightarrow {OR} = \overrightarrow vOP=u,OR=v, and OQ→=αu→+βv→\overrightarrow {OQ} = \alpha \overrightarrow u + \beta \overrightarrow vOQ=αu+βv, then α,β2\alpha ,{\beta ^2}α,β2 are the roots of the equation :Ax2+x−2=0{x^2} + x - 2 = 0x2+x−2=0B3x2+2x−1=03{x^2} + 2x - 1 = 03x2+2x−1=0C3x2−2x−1=03{x^2} - 2x - 1 = 03x2−2x−1=0Dx2−x−2=0{x^2} - x - 2 = 0x2−x−2=0Check answerSkip