PhysicsEasy183×since 2002Q5957An alpha nucleus of energy 12mv2{1 \over 2}m{v^2}21mv2 bombards a heavy nuclear target of charge ZeZeZe. Then the distance of closest approach for the alpha nucleus will be proportional toAv2{v^2}v2B1m{1 \over m}m1C1v2{1 \over {{v^2}}}v21D1Ze{1 \over {Ze}}Ze1Check answerSkip