ChemistryEasy84×since 2003Q1234H2O2\mathrm{H}_{2} \mathrm{O}_{2}H2O2 acts as a reducing agent in :AMn2++2H2O2→MnO2+2H2O\mathrm{Mn}^{2+}+2 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{MnO}_{2}+2 \mathrm{H}_{2} \mathrm{O}Mn2++2H2O2→MnO2+2H2OB2Fe2++2H++H2O2→2Fe3++2H2O2 \mathrm{Fe}^{2+}+2 \mathrm{H}^{+}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{Fe}^{3+}+2 \mathrm{H}_{2} \mathrm{O}2Fe2++2H++H2O2→2Fe3++2H2OCNa2S+4H2O2→Na2SO4+4H2O\mathrm{Na}_{2} \mathrm{S}+4 \mathrm{H}_{2} \mathrm{O}_{2} \rightarrow \mathrm{Na}_{2} \mathrm{SO}_{4}+4 \mathrm{H}_{2} \mathrm{O}Na2S+4H2O2→Na2SO4+4H2OD2NaOCl+H2O2→2NaCl+H2O+O22 \mathrm{NaOCl}+\mathrm{H}_{2} \mathrm{O}_{2} \rightarrow 2 \mathrm{NaCl}+\mathrm{H}_{2} \mathrm{O}+\mathrm{O}_{2}2NaOCl+H2O2→2NaCl+H2O+O2Check answerSkip