PhysicsMedium85×since 2002Q8478A wave travelling along the xxx-axis is described by the equation y(x,t)=0.005y(x, t)=0.005y(x,t)=0.005 cos (α x−βt).\cos \,\left( {\alpha \,x - \beta t} \right).cos(αx−βt). If the wavelength and the time period of the wave are 0.080.080.08 mmm and 2.0s2.0s2.0s, respectively, then α\alphaα and β\betaβ in appropriate units areAα=25.00π, β=π\alpha = 25.00\pi ,\,\beta = \piα=25.00π,β=πBα=0.08π, β=2.0π\alpha = {{0.08} \over \pi },\,\beta = {{2.0} \over \pi }α=π0.08,β=π2.0Cα=0.04π, β=1.0π\alpha = {{0.04} \over \pi },\,\beta = {{1.0} \over \pi }α=π0.04,β=π1.0Dα=12.50π, β=π2.0\alpha = 12.50\pi ,\,\beta = {\pi \over {2.0}}α=12.50π,β=2.0πCheck answerSkip