MathematicsMedium202×since 2002Q5772A vector a→=αi^+2j^+βk^(α,β∈R)\overrightarrow a = \alpha \widehat i + 2\widehat j + \beta \widehat k\left( {\alpha ,\beta \in R} \right)a=αi+2j+βk(α,β∈R) lies in the plane of the vectors, b→=i^+j^\overrightarrow b = \widehat i + \widehat jb=i+j and c→=i^−j^+4k^\overrightarrow c = \widehat i - \widehat j + 4\widehat kc=i−j+4k. If a→\overrightarrow aa bisects the angle between b→\overrightarrow bb and c→\overrightarrow cc, then:Aa→.i^+3=0\overrightarrow a .\widehat i + 3 = 0a.i+3=0Ba→.k^−4=0\overrightarrow a .\widehat k - 4 = 0a.k−4=0Ca→.i^+1=0\overrightarrow a .\widehat i + 1 = 0a.i+1=0Da→.k^+2=0\overrightarrow a .\widehat k + 2 = 0a.k+2=0Check answerSkip