MathematicsMedium249×since 2002Q2457A vector v⃗\vec{v}v in the first octant is inclined to the xxx-axis at 60∘60^{\circ}60∘, to the yyy-axis at 45 and to the zzz-axis at an acute angle. If a plane passing through the points (2,−1,1)(\sqrt{2},-1,1)(2,−1,1) and (a,b,c)(a, b, c)(a,b,c), is normal to v⃗\vec{v}v, then :Aa+b+2c=1a+b+\sqrt{2} c=1a+b+2c=1B2a+b+c=1\sqrt{2} a+b+c=12a+b+c=1C2a−b+c=1\sqrt{2} a-b+c=12a−b+c=1Da+2b+c=1a+\sqrt{2} b+c=1a+2b+c=1Check answerSkip