PhysicsHard148×since 2002Q7999A sphere of relative density σ\sigmaσ and diameter DDD has concentric cavity of diameter ddd. The ratio of Dd\frac{D}{d}dD, if it just floats on water in a tank is :A(σ−2σ+2)1/3\left(\frac{\sigma-2}{\sigma+2}\right)^{1 / 3}(σ+2σ−2)1/3B(σ+1σ−1)1/3\left(\frac{\sigma+1}{\sigma-1}\right)^{1 / 3}(σ−1σ+1)1/3C(σ−1σ)1/3\left(\frac{\sigma-1}{\sigma}\right)^{1 / 3}(σσ−1)1/3D(σσ−1)1/3\left(\frac{\sigma}{\sigma-1}\right)^{1 / 3}(σ−1σ)1/3Check answerSkip