PhysicsEasy145×since 2002Q6606A small object at rest, absorbs a light pulse of power 20 mW20 \mathrm{~mW}20 mW and duration 300 ns300 \mathrm{~ns}300 ns. Assuming speed of light as 3×108 m/s3 \times 10^{8} \mathrm{~m} / \mathrm{s}3×108 m/s, the momentum of the object becomes equal to :A1×10−17 kg m/s1 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}1×10−17 kg m/sB0.5×10−17 kg m/s0.5 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}0.5×10−17 kg m/sC3×10−17 kg m/s3 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}3×10−17 kg m/sD2×10−17 kg m/s2 \times 10^{-17} \mathrm{~kg} \mathrm{~m} / \mathrm{s}2×10−17 kg m/sCheck answerSkip