PhysicsMedium94×since 2002Q5910A series LCR circuit has L=0.01 H,R=10 Ω\mathrm{L}=0.01\, \mathrm{H}, \mathrm{R}=10\, \OmegaL=0.01H,R=10Ω and C=1μF\mathrm{C}=1 \mu \mathrm{F}C=1μF and it is connected to ac voltage of amplitude (Vm)50 V\left(\mathrm{V}_{\mathrm{m}}\right) 50 \mathrm{~V}(Vm)50 V. At frequency 60%60 \%60% lower than resonant frequency, the amplitude of current will be approximately :A466 mAB312 mAC238 mAD196 mACheck answerSkip