PhysicsMedium94×since 2002Q5927A series L.R circuit connected with an ac source E=(25sin1000t)VE=(25 \sin 1000 t) VE=(25sin1000t)V has a power factor of 12\frac{1}{\sqrt{2}}21. If the source of emf is changed to E=(20sin2000t)V\mathrm{E}=(20 \sin 2000 \mathrm{t}) \mathrm{V}E=(20sin2000t)V, the new power factor of the circuit will be :A13\frac{1}{\sqrt{3}}31B12\frac{1}{\sqrt{2}}21C15\frac{1}{\sqrt{5}}51D17\frac{1}{\sqrt{7}}71Check answerSkip