PhysicsMedium251×since 2002Q7494A sample of gas at temperature TTT is adiabatically expanded to double its volume. The work done by the gas in the process is (given,γ=32)\left(\mathrm{given}, \gamma=\frac{3}{2}\right)(given,γ=23) :AW=TR[2−2]W=T R[\sqrt{2}-2]W=TR[2−2]BW=TR[2−2]W=\frac{T}{R}[\sqrt{2}-2]W=RT[2−2]CW=RT[2−2]W=\frac{R}{T}[2-\sqrt{2}]W=TR[2−2]DW=RT[2−2]W=R T[2-\sqrt{2}]W=RT[2−2]Check answerSkip