PhysicsMedium63×since 2002Q6198A rod of length L has non-uniform linear mass density given by ρ\rhoρ(x) = a+b(xL)2a + b{\left( {{x \over L}} \right)^2}a+b(Lx)2 , where a and b are constants and 0 ≤\le≤ x ≤\le≤ L. The value of x for the centre of mass of the rod is at :A32(a+b2a+b)L{3 \over 2}\left( {{{a + b} \over {2a + b}}} \right)L23(2a+ba+b)LB43(a+b2a+3b)L{4 \over 3}\left( {{{a + b} \over {2a + 3b}}} \right)L34(2a+3ba+b)LC34(2a+b3a+b)L{3 \over 4}\left( {{{2a + b} \over {3a + b}}} \right)L43(3a+b2a+b)LD32(2a+b3a+b)L{3 \over 2}\left( {{{2a + b} \over {3a + b}}} \right)L23(3a+b2a+b)LCheck answerSkip