MathematicsMedium128×since 2002Q5499A ray of light along x+3y=3x + \sqrt 3 y = \sqrt 3x+3y=3 gets reflected upon reaching XXX-axis, the equation of the reflected ray is :Ay=x+3y = x + \sqrt 3y=x+3B3y=x−3\sqrt 3 y = x - \sqrt 33y=x−3Cy=3x−3y = \sqrt 3 x - \sqrt 3y=3x−3D3y=x−1\sqrt 3 y = x - 13y=x−1Check answerSkip