PhysicsEasy183×since 2002Q6103A radioactive sample is undergoing α\alphaα decay. At any time t₁, its activity is A and another time t₂, the activity is A5{A \over 5}5A. What is the average life time for the sample?Aln5t2−t1{{\ln 5} \over {{t_2} - {t_1}}}t2−t1ln5Bln(t2+t1)2{{\ln ({t_2} + {t_1})} \over 2}2ln(t2+t1)Ct1−t2ln5{{{t_1} - {t_2}} \over {\ln 5}}ln5t1−t2Dt2−t1ln5{{{t_2} - {t_1}} \over {\ln 5}}ln5t2−t1Check answerSkip