PhysicsHard145×since 2002Q6591A proton, an electron and an alpha particle have the same energies. Their de-Broglie wavelengths will be compared as :Aλp>λe>λα\lambda_{\mathrm{p}}>\lambda_{\mathrm{e}}>\lambda_\alphaλp>λe>λαBλα<λp<λe\lambda_\alpha<\lambda_{\mathrm{p}}<\lambda_{\mathrm{e}}λα<λp<λeCλe>λα>λp\lambda_{\mathrm{e}}>\lambda_\alpha>\lambda_{\mathrm{p}}λe>λα>λpDλp<λe<λα\lambda_{\mathrm{p}}<\lambda_{\mathrm{e}}<\lambda_\alphaλp<λe<λαCheck answerSkip