PhysicsEasy46×since 2002Q6942A point dipole p→=−p0x^\overrightarrow p = - {p_0}\widehat xp=−p0x is kept at the origin. The potential and electric field due to this dipole on the y-axis at a distance d are, respectively: (Take V= 0 at infinity)A∣p→∣4π∈0d2,−p→4π∈0d3{{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}4π∈0d2∣p∣,4π∈0d3−pB0,p→4π∈0d30,{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}0,4π∈0d3pC∣p→∣4π∈0d2,p→4π∈0d3{{\left| {\overrightarrow p } \right|} \over {4\pi { \in _0}{d^2}}},{{\overrightarrow p } \over {4\pi { \in _0}{d^3}}}4π∈0d2∣p∣,4π∈0d3pD0,−p→4π∈0d30,{{ - \overrightarrow p } \over {4\pi { \in _0}{d^3}}}0,4π∈0d3−pCheck answerSkip