MathematicsMedium249×since 2002Q2418A plane P meets the coordinate axes at A, B and C respectively. The centroid of Δ\DeltaΔABC is given to be (1, 1, 2). Then the equation of the line through this centroid and perpendicular to the plane P is :Ax−11=y−11=z−22{{x - 1} \over 1} = {{y - 1} \over 1} = {{z - 2} \over 2}1x−1=1y−1=2z−2Bx−12=y−11=z−21{{x - 1} \over 2} = {{y - 1} \over 1} = {{z - 2} \over 1}2x−1=1y−1=1z−2Cx−12=y−12=z−21{{x - 1} \over 2} = {{y - 1} \over 2} = {{z - 2} \over 1}2x−1=2y−1=1z−2Dx−11=y−12=z−22{{x - 1} \over 1} = {{y - 1} \over 2} = {{z - 2} \over 2}1x−1=2y−1=2z−2Check answerSkip