PhysicsEasy156×since 2002Q8305A physical quantity 'y' is represented by the formula y=m2r−4gxl−32y = {m^2}{r^{ - 4}}{g^x}{l^{ - {3 \over 2}}}y=m2r−4gxl−23 If the percentage errors found in y, m, r, l and g are 18, 1, 0.5, 4 and p respectively, then find the value of x and p.A5 and ±\pm±2B4 and ±\pm±3C163{{16} \over 3}316 and ±32\pm {3 \over 2}±23D8 and ±\pm± 2Check answerSkip