PhysicsMedium65×since 2002Q7837A person travels xxx distance with velocity v1v_{1}v1 and then xxx distance with velocity v2v_{2}v2 in the same direction. The average velocity of the person is v\mathrm{v}v, then the relation between v,v1v, v_{1}v,v1 and v2v_{2}v2 will be.AV=V1+V2\mathbf{V}=\mathbf{V}_{1}+\mathbf{V}_{2}V=V1+V2BV=v1+V22V=\frac{v_{1}+V_{2}}{2}V=2v1+V2C1v=1v1+1v2\frac{1}{\mathrm{v}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}}v1=v11+v21D2 V=1v1+1v2\frac{2}{\mathrm{~V}}=\frac{1}{\mathrm{v}_{1}}+\frac{1}{\mathrm{v}_{2}} V2=v11+v21Check answerSkip