MathematicsMedium249×since 2002Q2409A perpendicular is drawn from a point on the line x−12=y+1−1=z1{{x - 1} \over 2} = {{y + 1} \over { - 1}} = {z \over 1}2x−1=−1y+1=1z to the plane x + y + z = 3 such that the foot of the perpendicular Q also lies on the plane x – y + z = 3. Then the co-ordinates of Q are :A(4, 0, – 1)B(2, 0, 1)C(1, 0, 2)D(– 1, 0, 4)Check answerSkip