PhysicsEasy100×since 2002Q8162A particle starts executing simple harmonic motion (SHM) of amplitude 'a' and total energy E. At any instant, its kinetic energy is 3E4{{3E} \over 4}43E then its displacement 'y' is given by :Ay = aBy=a2y = {a \over {\sqrt 2 }}y=2aCy=a32y = {{a\sqrt 3 } \over 2}y=2a3Dy=a2y = {a \over 2}y=2aCheck answerSkip