PhysicsMedium42×since 2002Q6273A particle of mass m is suspended from a ceiling through a string of length L. The particle moves in a horizontal circle of radius r such that r=L2r = {L \over {\sqrt 2 }}r=2L. The speed of particle will be :Arg{\sqrt {rg} }rgB2rg{\sqrt {2rg} }2rgC2rg{2\sqrt {rg} }2rgDrg2{\sqrt {{{rg} \over 2}} }2rgCheck answerSkip