PhysicsMedium100×since 2002Q8135A particle of mass mmm executes simple harmonic motion with amplitude a and frequency v.v.v. The average kinetic energy during its motion from the position of equilibrium to the end isA2π2 ma2v22{\pi ^2}\,m{a^2}{v^2}2π2ma2v2Bπ2 ma2v2{\pi ^2}\,m{a^2}{v^2}π2ma2v2C14 ma2v2{1 \over 4}\,m{a^2}{v^2}41ma2v2D4π2ma2v24{\pi ^2}m{a^2}{v^2}4π2ma2v2Check answerSkip