PhysicsEasy70×since 2002Q8586A particle of mass 500 gm is moving in a straight line with velocity v = b x^5/2. The work done by the net force during its displacement from x = 0 to x = 4 m is : (Take b = 0.25 m^−-−3/2 s^−-−1).A2 JB4 JC8 JD16 JCheck answerSkip