PhysicsEasy145×since 2002Q6550A particle moving with kinetic energy E has de Broglie wavelength λ\lambdaλ. If energy Δ\DeltaΔE is added to its energy, the wavelength become λ\lambdaλ/2. Value of Δ\DeltaΔE, is :AEB3EC2ED4ECheck answerSkip