PhysicsMedium70×since 2002Q8579A particle is moving in a circular path of radius aaa under the action of an attractive potential U=−k2r2U = - {k \over {2{r^2}}}U=−2r2k Its total energy is:A−32ka2- {3 \over 2}{k \over {{a^2}}}−23a2kBZeroC−k4a2- {k \over {4{a^2}}}−4a2kDk2a2{k \over {2{a^2}}}2a2kCheck answerSkip